Question
La presión osmótica medida de una disolución acuosa $0.010 \mathrm{M}$ de $\mathrm{CaCl}_2$ es de $0.674 \mathrm{~atm}$ a $25^{\circ} \mathrm{C}$. (a) Calcule el factor de van't Hoff, $i$, de la disolución. (b) ¿Cómo cabe esperar que cambie el valor de $i$ al aumentar la concentraciốn de la disolución? Explique
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010 \, \text{M}$ - Osmotic pressure, $\Pi = 0.674 \, \text{atm}$ - Temperature, $T = 25^\circ \text{C}$ Show more…
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The osmotic pressure of a $0.010 \mathrm{M}$ aqueous solution of $\mathrm{CaCl}_{2}$ is found to be 0.674 atm at $25^{\circ}$ C. (a) Calculate the van't Hoff factor, $i$, for the solution. (b) How would you expect the value of $i$ to change as the solution becomes more concentrated? Explain.
The osmotic pressure of a 0.010$M$ aqueous solution of $\mathrm{CaCl}_{2}$ is found to be 0.674 atm at $25^{\circ} \mathrm{C}$ . Calculate the van't Hoff factor, $i,$ for the solution.
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