00:02
In question 98 has three parts.
00:06
The first part, we have to draw a structure for lactose.
00:14
Now, lactose has a disaccharide, so we've got two sugar molecules connected.
00:22
Those are going to be galactose and glucose.
00:41
Galactose has the following structure.
00:46
It's a six -membered ring.
00:47
We have our oxygen here, we'll draw our substituents.
01:26
We've got h and oh on most of our carbons.
01:50
Now, normally, the oh would actually be on the bottom here, but as we'll see pretty soon here, that's going to change as we construct the entire molecule.
02:08
So we're going to number these carbons.
02:11
We've got one, two, three, four, five, and six.
02:24
Now, according to the problem, galactose is bonded through c1, bonded to glucose, that is.
02:45
Glucose is bonded through c4, which we'll get too soon, and the type of linkage is a beta glycosidic linkage.
02:55
Because it's a beta glycosidic linkage, the oh on galactose goes up, and then glucose connects through that.
03:23
We're going to draw glucose.
03:27
Now the figure given in the book for glucose is aligned in the same way as galactose.
03:36
The problem is we got to draw c4 on this size.
03:40
So what we're going to do is flip the molecule over.
03:46
So it's going to look like this.
03:56
Oxygen down here.
04:03
Then we'll add a substituence.
04:09
This is flipped.
04:11
The o's and the ohs and hs are going to be.
04:15
Flipped as well.
04:45
And this carbon is carbon four, four, five, six, three, two, one.
04:57
And it's going to be bound to galactose through here...