$\Lambda$ particle in cquilibrium displaces from $(1,1,2) \mathrm{m}$ to $(2,0,3) \mathrm{m} .$ If onc of the forces acting on the particle is $(\hat{i} \quad \hat{j} \mid 3 \hat{k}) \mathrm{N}$, total work done by the remaining forces acting on the particle is
(a) $5 \mathrm{~J}$
(b) $-5 \mathrm{~J}$
(c) Zero
(d) $10 \mathrm{~J}$