00:01
So we are considering four coins which are being tossed together.
00:07
So now think if we toss four coins together, we will get either a head or a tail on each of them.
00:15
So what should be the number of total possible outcomes? it will be 2 into 2 into 2, 2 into 2, which is 16.
00:25
So let us see how that is going to happen.
00:28
So think in the first place if it comes ahead.
00:31
Then it can split into two options, right? either a head or a tail.
00:37
Like in the first place, if we are considered there is one head, then in the second one, we can have either a head or a tail.
00:46
Now, if we have a head, then again for the third coin, we can again have a head or a tail, or if the second coin was tail, then we can again have head or a tail for the third coin.
00:58
That means in the second coin, if it is head, then also we have third and third coin being head or tail same way even if we have the second coin being tail the third coin can still have head or tail and then for each of them it will be head tail head tail head tail and head tail well this thing is called oops a tree diagram okay now the catch here is we considered the first place will be head but the same thing will be there for second one t also so what will be the total number of sample space in the sample space will be h h h h h h h then h h then again see h h h t h, correct, so h, h, t.
02:07
Now, in the third place also, we will again have h t.
02:12
Now again, h, h, h, t, h t, h t, h t, h t, h t, t.
02:31
Same way now, just think we have to have the first place replaced with t, t, t, t, correct.
02:38
So we will have all these answers.
02:40
So t -h -h -h, then t -h -t -h -t -t -t -h -t -h -t -t -h -t -h -t -h and t -t -t -h -h and 4 times t.
03:05
Correct? now there is a random variable that assigns a number on each of these outcomes based on the number of heads.
03:19
So what is the number of heads here? so let's denote it with a red color.
03:25
So that it is easy...