00:01
So in this problem, laser light of web length 632 .8 nanometer hits either single slit or double slit that we don't know yet.
00:12
The diffraction patterns form at a distance 2 .6 meter from the slit.
00:19
The figure 38 .48 in the statement of the problem shows the diffraction pattern and the distances between them with a centimeter.
00:30
Centimeter ruler there.
00:33
So in problem a, the part a of the problem, in part a, we want to find out whether the diffraction pattern corresponds to the single slit or double slit.
00:47
Now since the width of the central maximum seems twice as wide as the other ones, the slit used must be single slate.
00:55
Okay, so i'm going to write down single slate here.
01:03
So this is the answer, but also to reinforce our claim, the double slit maxima are evenly spaced, which it is not the case here in the figure.
01:18
So this makes sure that the slit that was being used is the single slate.
01:23
Now, in part b of the experiment, the part b of the problem, to find the width of this slate, we find the distances between the two second maximum first, and it is 2y, just following the figure, 2y, which is the distance between the two second order minimum.
01:51
Then this is going to be equal to 11 .7 centimeters minus 6 .3 centimeters, which is going to go.
02:04
Give us 5 .4 centimeters...