00:01
Hello there.
00:02
Welcome to problem number 60.
00:05
In this problem we are given an electron that has a principal quantum number of four.
00:15
So if we think about the other quantum numbers for this, the l, remember, ranges from zero to n minus one.
00:26
So that means l can be zero, one, two, or three.
00:32
And remember this corresponds to the sub -levels.
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When l equals zero, we have an s -orbital.
00:40
When l is 1, it's a p -orbital.
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When l is 2, it's a d, and when l is 3, it's an f -orbital.
00:48
We are also given in this problem that the magnetic quantum number, m -sub -l, is equal to 2.
00:58
And that is the information that we are given.
01:00
If we think, i'll come back to that.
01:02
Let's go ahead and look at the problems here.
01:04
So letter a.
01:09
I've just talked about letter a.
01:12
It is in fact true because n equals 4.
01:17
So the electron would be found in the fourth energy level since n equals 4.
01:31
All right.
01:32
So a is true...