Lead shielding. When gamma rays are incident on matter, the intensity of the gamma rays passing through the material varies with depth $x$ as $I(x)=I_{0} e^{-\mu x}$ , where $I_{0}$ is the intensity of the radiation at the surface of the material and $\mu$ is the absorption coefficient. For $0.400-$ MeV gamma rays in lead, the absorption coefficient is 1.59 $\mathrm{cm}^{-1}$ .(a) Determine the "half-thickness" for lead, that is, the thickness of lead that would absorb half the incident gamma rays. (b) What thickness reduces the radiation by a factor of $10^{4} ?$