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Left and right Riemann sums Complete the followin…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81

Problem 28 Easy Difficulty

Left and right Riemann sums Complete the following steps for the given function, interval, and value of $n.$
a. Sketch the graph of the function on the given interval.
b. Calculate $\Delta x$ and the grid points $x_{0}, x_{1}, \ldots, x_{n^{*}}.$
c. Illustrate the left and right Riemann sums. Then determine which Riemann sum underestimates and which sum overestimates the area under the curve.
d. Calculate the left and right Riemann sums.
$$f(x)=\sin ^{-1} \frac{x}{3} \text { on }[0,3] ; n=6$$

Answer

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Chapter 5

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Section 1

Approximating Areas under Curves

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Video Transcript

Okay, so I just did a quick Google search saying Dez, most Riemann sums and the very first thing that popped up was a program that you could just type in the equation. So I went ahead and did that already. Inverse sign of X over three. And give your left endpoint, which already typed in equals three. You're right in point vehicles so equals zero B equals three. And then you could tell how many rectangles you want in this picture. So I choosing six. Now, you might be looking at this and saying, You don't really see the rectangles. It's this First one is really small. The second one stops it. X equals one and 1 to 1.5. And this shouldn't make sense that your change in X is 0.5. Because if we're going from 0 to 3, you subtract your bounds and you divide by six. Then each width needs to be 0.5. Now, this next thing you either type in zero for left handsome one for right, handsome or 10.5 for midpoint. I'm just gonna go ahead and do zero first because they want the left hand. Some is your answer first. So as this neat little formula for you will tell you what you're correct, answer is. And what this does is it saves you from figuring out what in verse sign of zero is which is actually zero, which makes perfect sense. Um, saves you from typing an inverse sign of 0.5 divided by three. Um, you know, because this value 0.167 you'd have to feel like it's not on the unit circle. This one is. I could have figured out what inverse sign of 1.5 s. Mhm. Okay, um, these values are what you do. So if you're doing this by hand, you would have 0.5 times zero plus 0.5 times 0.167 That's the area of this rectangle plus 0.5 the area the width of this directing all times 0.34 plus 0.5 times per five or six. That's the area of this rectangle. It's really it's not outlined. Plus 0.5 times 2.73 plus 0.5 times 0.95. So if you have a teacher that needs to see that work, that's what you would do and your answer is 1.373 So let's do the right remind some, which I just have to change. That could be one. And all of those values that I was talking about earlier are the same. But the difference is you don't do 0.5 times zero now because I was the left hand you 2.5 times pi over two and add everything else together and notice how my son changes to 2.158 It's a larger value, so thanks for watching.

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