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$$\left(2, \frac{1}{3}\right),\left\{\begin{array}{l}{x-3 y=1} \\{-2 x+6=-6 y}\end{array}\right.$$
no, the ordered pair is not a solution of given system of equations
Algebra
Chapter 4
Systems of Linear Equations and Inequalities
Section 1
Solving Systems of Equations by Graphing
Equations and Inequalities
Systems of Equations and Inequalities
Campbell University
Oregon State University
Harvey Mudd College
Lectures
01:32
In mathematics, the absolu…
01:11
03:57
$$\begin{array}{l}{\te…
00:36
Solve.$2 x-3 y=6,$ for…
01:16
Solve.$$\begin{aligned…
02:02
Solve.$$\begin{arr…
01:50
Solve for $x$ and $y$.…
02:11
Solve Problems.$\begin…
00:49
If $y=\frac{2}{3} x+1,$ fi…
00:46
Solve the equation for $y$…
00:22
Solve each equation for $y…
03:02
$$\begin{array}{l}{\frac{d…
So you gotta order a pair of two and 1/3. I got our system of equations. X minus three y equals one. Okay, The second equation negative two X plus six equals negative. 61 So they asked us about a solution. We plug it in so we plug in to your acts 1/3 for why? See, three times authorities one and two minus one equals one that checks out, then the other equation negative two times X plus six equals negative. Six times. Why? Maybe the two times two is negative for so negative. Four plus six and the negative six times. The third is negative, too. And I also checks out checks out on both the equations. So it's a suit.
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