We can use the identities $1 + \cos \theta = 2 \cos^2 \frac{\theta}{2}$ and $\sin \theta = 2 \sin \frac{\theta}{2} \cos \frac{\theta}{2}$ to rewrite the expression as $\left[\frac{2 \cos^2 \frac{\pi}{16} + i \cdot 2 \sin \frac{\pi}{16} \cos \frac{\pi}{16}}{2
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