00:01
In this problem, i have a, b, squared, c, all taken to the negative third power, and then b to the negative third power, and the denominator, all squared.
00:16
The first thing i'm going to do is i'm going to handle the negative exponents in the inside of the parentheses.
00:22
I'm going to do that by moving this b to the negative third to the numerator and making it a positive b to the third.
00:30
I'm then going to take this entire set of parentheses, a, b, squared, c, move that entire thing to the denominator and make that exponent positive.
00:41
And i will square my answers.
00:47
At this point, i'm still working inside the parentheses.
00:50
That leaves me with b to the third, a to the third, b to the sixth, c to the third, when i distribute the three, the exponent of three to all of the terms in the parentheses.
01:05
At this point right now, i have three bs in the numerator and six bs in the denominator...