Question
$\left(x^{2}-1\right) y^{\prime \prime}+(1-x) y^{\prime}+\left(x^{2}-2 x+1\right) y=0$
Step 1
The standard form of a second order linear differential equation is $y'' + p(x)y' + q(x)y = 0$. To do this, we divide the entire equation by $x^2 - 1$: \[y'' + \frac{1-x}{x^2-1}y' + \frac{x^2-2x+1}{x^2-1}y = 0\] Show more…
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