Problem

$\left\{\sin ^{2} x, \cos ^{2} x, 1\right\} \quad…

Problem 8 Easy Difficulty

$\left\{x^{2}, x^{2}-1,5\right\} \quad$ on $(-\infty, \infty)$

Answer

$$
x^{2}-1
$$

Related Courses

Calculus 1 / AB

Fundamentals of Differential Equations

Chapter 6

Theory of Higher-Order Linear Differential Equations

Section 1

Basic Theory of Linear Differential Equations

Discussion

You must be signed in to discuss.

Top Calculus 1 / AB Educators

Watch More Solved Questions in Chapter 6

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Video Transcript

so I was sure you just said off ex squids X squared minus one or 51 of short, if this is you nearly independent or dependents now lets their constant C won't. Morse played by explored lost sit soo mortar blind by X squared, minus worn loss. Sit Torri. More supplied by five less because zero The only way this sets will Belinelli Independence is if she won't sit through Unsanitary isn't course zero. But if at least one of them isn't is not about zero, then their dependence. Now let's take it. Let's make it. Let's expand. Is this a B C one X squared? Lost seats Who? X squared minus seeds. Ooh, plus five C 3/4 0 Now let's see if we can play a game here to see if we can eliminate these. No, let's take 61 to you also warn, See through to be able to minus one. So we're gonna have X squared minus X squared. Lost one plus five seed. Three equals zero. So this will concert dates defied sick C three to quart of minus one over five. I'm gonna have that zero. It course zero. So we see that with C one records, one seat, two quarts of minus one seat, three quarts of miners, one over five. We have that This will be equal to zero, so this implies that this is linearly dependent. It's implies linearly dependence because we're able to find non zero constants that's make this to be the course, is there?

We have video lessons for 79.62% of the questions in this textbook