Question
$$\left(x^{3}+y^{3}\right)=3 x y^{2} \frac{\mathrm{d} y}{\mathrm{~d} x}$$
Step 1
Step 1: First, we rewrite the given differential equation as follows: $$ \frac{dy}{dx} = \frac{x^3 + y^3}{3xy^2} $$ We can then make the substitution $y = vx$, which gives us $\frac{dy}{dx} = v + x\frac{dv}{dx}$. Show more…
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Key Concepts
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