00:01
Hi, here in this given problem there are the two springs which are arranged in parallel.
00:10
This is a platform which is being pressed by the foot like this by applying a force f on it.
00:24
Work done on compressing the spring that is given as w is equal to 77 .0 joules and compression in the spring x is equal to 0 .210 meter.
01:03
In the first part of the problem we have to find force applied being applied by the foot on the platform.
01:11
So first of all using work energy theorem, work done on the board will be equal to elastic potential energy stored in the spring.
01:32
So this k, force constant of the combined spring system will be given by 2 ys of w divided by x square.
01:43
Means this is two times of 77 divided by square of 0 .210.
01:51
So, k is calculated to be equal to 3 ,492 .06 newton per meter.
02:00
So force being applied by the foot on the board, f, will be given by kx...