Question
Length of a wire of resistance $R \Omega$ is increased to 10 times, so its resistance becomes $1000 \Omega$, therefore $R=\ldots .$ (The volume of the wire remains same during increase in length)(A) $0.01 \Omega$(B) $0.1 \Omega$(C) $1 \Omega$(D) $10 \Omega$
Step 1
Step 1: We know that the resistance $r$ of a wire is given by the formula $r = \rho \frac{l}{a}$, where $\rho$ is the resistivity, $l$ is the length, and $a$ is the cross-sectional area of the wire. Show more…
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Round 2
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