00:01
For this problem, we have been given a generic matrix a, which is an n -by -n -n -symmetric matrix.
00:07
Now, if you recall the definition of a symmetric matrix, a matrix is going to be symmetric if the transpose of the matrix equals the matrix itself.
00:18
We're going to use that definition as we're doing some of these proofs here.
00:23
So two things we want to do in this exercise.
00:26
First, we want to show that a squared is also symmetric.
00:35
In other words, we want to show that if i take the transpose of a squared, that that equals a squared.
00:45
This is what i would like to show.
00:48
So let's start with the left -hand side.
00:50
I have a -squared, and i'm going to take the transpose of it.
00:54
Well, a -squared is a times a.
00:58
And when i take the transpose of a product, i'm going to put this over the side in blue just so it doesn't get mixed up here.
01:04
If i had two matrices, let's call them c and d, and i take the transpose of their product, it is the transpose of the second matrix times the transpose of the first...