00:01
For the solution, we can compute the derivative of c of t is equal to x to k of t using the chain rule.
00:07
So taking the derivative dcdt, so by the chain rule, this is taking the derivative of x k of t, that's going to be equal to k, dx, dt, and then times kt.
00:28
So since we have that x of t satisfies the system, we know that the derivative, dxdt kt is equal to a x vector times kt.
00:38
So therefore we have that d -c -d -t is going to be equal to k times a -x vector k -t, which is equal to k -a -c vector of t.
00:54
And this shows that then c of t is equal to x vector of kt satisfies the system.
01:02
And then comparing the vector fields, well, the vector fields of both systems are going to be linearly related, but they differ in how fast trajectories are traversed.
01:21
So we have our first system, which would be dx, dt, is equal to ax...