To show that \((a_n)\) is increasing, we need to prove that \(a_{n+1} > a_n\) for all \(n \geq 1\).
Starting with the recursive definition, we have:
\[
a_{n+1} = \sqrt{2 a_n}.
\]
We want to show that:
\[
\sqrt{2 a_n} > a_n.
\]
Squaring both sides (since both
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