Question
Let $a+b=4, a<2$ and $g(x)$ be a monotonically increasing function of $x$. Then, $f(a)=\int_{0}^{a} g(x) d x+\int_{0}^{b} g(x) d x$(A) increases with increase in $(b-a)$(B) decreases with increase in $(b-a)$
Step 1
From this, we can write $b=4-a$. Show more…
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Monotonocity
Level III
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