Question
Let $A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]$ be a real matrix. Find necessary and sufficicnt conditions on $a, b, c, d$ so that $A$ is diagonalizable - that is, so that $A$ has two (real) linearly independent eigenvectors.
Step 1
For a 2x2 matrix, the characteristic polynomial is given by $\lambda^{2} - \text{tr}(A)\lambda + \text{det}(A)$, where $\text{tr}(A)$ is the trace of the matrix (the sum of the diagonal elements) and $\text{det}(A)$ is the determinant of the matrix. Show more…
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Let $A=\left[\begin{array}{rr}{1} & {1} \\ {-1} & {3}\end{array}\right]$ and $\mathcal{B}=\left\{\mathbf{b}_{1}, \mathbf{b}_{2}\right\},$ for $\mathbf{b}_{1}=\left[\begin{array}{l}{1} \\ {1}\end{array}\right]$ $\mathbf{b}_{2}=\left[\begin{array}{l}{5} \\ {4}\end{array}\right] .$ Define $T : \mathbb{R}^{2} \rightarrow \mathbb{R}^{2}$ by $T(\mathbf{x})=A \mathbf{x}$ a. Verify that $\mathbf{b}_{1}$ is an eigenvector of $A$ but $A$ is not diagonalizable. b. Find the $\mathcal{B}$ -matrix for $T$
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