Let
$$
A=\left[\begin{array}{lll}
1 & 1 & 0 \\
1 & 0 & 0 \\
0 & 0 & 0 \\
0 & 0 & 0
\end{array}\right], \mathcal{X}=\operatorname{span}\left\{\left[\begin{array}{l}
1 \\
1 \\
1
\end{array}\right],\left[\begin{array}{l}
1 \\
0 \\
1
\end{array}\right]\right\} \text { and } \mathcal{Y}=\operatorname{span}\left\{\left[\begin{array}{l}
1 \\
0 \\
1 \\
1
\end{array}\right],\left[\begin{array}{l}
1 \\
1 \\
1 \\
0
\end{array}\right]\right\}
$$
Find a pseudoinverse $A^{\circ}$ of the matrix $A$ such that $\mathcal{N}_{A^{\circ}}=\mathcal{Y}$ and $\mathcal{R}_{A^{\circ}}=\mathcal{X}$.