$GF_9$ is the finite field with $9$ elements. Since $9 = 3^2$, $GF_9$ can be constructed as $\mathbb{F}_3[x]/(p(x))$ where $p(x)$ is an irreducible polynomial of degree $2$ over $\mathbb{F}_3$. For simplicity, let's use $p(x) = x^2 + 1$, which is irreducible over
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