00:02
We are given two monic polynomials, f of t and g of t.
00:15
So these are of minimal degree.
00:22
Look, we're all familiar with the regular as.
00:27
Don't mean name, man.
00:29
Such that a is a root of each of these polynomials.
00:35
We're asked to show that f, h of t and g of t are the same.
00:51
Well, consider the function h of t, which is f of t minus g of t.
01:03
Well, notice that h of a, by definition, is f of a minus g of a.
01:11
And because a is a root of f of g and g of t, it follows that f of a and g of a are both zero...