Question
Let $\alpha, \beta, \gamma$ be the roots of the equation $3 x^{3}-x^{2}-3 x+1=0 .$ If $\alpha, \beta, \gamma$ are in H.P. then $|\alpha-\gamma|=$(A) $\frac{1}{3}$(B) $\frac{2}{3}$(C) $\frac{4}{3}$(D) None of these
Step 1
P.), we can write them as $\frac{1}{a-d}, \frac{1}{a}, \frac{1}{a+d}$ for some real numbers $a$ and $d$. Show more…
Show all steps
Your feedback will help us improve your experience
Manik Pulyani and 86 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If $\alpha, \beta, \gamma$ are the roots of $x^{3}+p x+q=0$, then $\left|\begin{array}{lll}\alpha & \beta & \gamma \\ \beta & \gamma & \alpha \\ \gamma & \alpha & \beta\end{array}\right|$ is (a) 0 (b) $\mathrm{p}^{3}$ (c) $\mathrm{pq}^{2}$ (d) 3
If alpha, beta, and gamma are the roots of x^3 + x^2 + 2x + 3 = 0, then the equation whose roots are beta + gamma, gamma + alpha, and gamma + beta is: A. x^3 + 2x^2 + 3x - 1 = 0 B. x^3 + 2x^2 + 3x + 1 = 0 C. x^3 + 2x^2 - 3x - 1 = 0 D. x^3 - 2x^2 + 3x - 1 = 0
If $\alpha, \beta$ be roots of $x^{2}+p x+1=0$ and $\gamma \delta \delta$ be the roots of $x^{2}+q x+1=0$, then $(\alpha-\gamma)(\beta-\gamma)(\alpha+\delta)(\beta+\delta)=$ (A) $p^{2}+q^{2}$ (B) $p^{2}-q^{2}$ (C) $q^{2}-p^{2}$ (D) None of these
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD