00:01
Hello, in this problem, we are given a function g of x is equal to squared of x for x greater than or equal to 0.
00:08
For letter a, we need to find the rate of change, rather the average rate of change at certain intervals for x.
00:15
So let's start from interval 1 to 2.
00:19
In order to solve that, let's just do delta y over delta x, and that will be equal to g of 2 minus g of 1 all over 2 minus 1 and this is equal to square of 2 minus 1 and that's approximately equal to 0 .4.
00:45
Then for the next one we have 1 to 1 .5.
00:53
So for that delta y over delta x equal to square of 1 .5 minus square of 1 over 1 .5 minus 1 .1.
01:06
And for this one let me just calculate this okay so for the second one this is approximately equal to point 45 so for this one from one to one plus h delta y over delta x is equal to square up one plus h minus square of one all over one plus h minus one so this is equal to square of one plus h minus 1 all over h.
02:24
So for the next part, we need to find the table for certain values of age.
02:30
So we have delta y over delta x at 1 to 1 plus h for certain values of age.
02:44
So let's start with 0 .1 here, 0 .01, 0 .001, and let's end at 0 .001.
02:56
So for 0 .1, we just plug in h in our equation here...