00:01
Okay, so suppose we're given three polynomials, x squared plus 1, x squared minus 1, and 2x minus 1.
00:13
Okay, and i want to show that these three polynomials form a basis for p2.
00:24
Okay, so how would we go about showing something like this? well, the first step that we would do is we'll transform, okay, these polynomials into a form that is more familiar to us.
00:37
We'll write them directly as column vectors, so transform to vectors.
00:43
And then once we have done that step, then to show that it is a basis for p2 is the same thing as showing that a set of vectors is a basis for, let's say, r3.
00:55
And then show vectors, form basis.
01:02
So that's the step that we'll take.
01:04
So how do we transform? these polynomials into a more familiar vector form.
01:11
So consider the following row vector 1 x squared.
01:17
Ok, so we can ask, ok, what is the column vector that we have to multiply this row vector by in order to get x squared plus 1? well, that column vector is going to be 1 ,0 .1.
01:33
The second column vector, ok, x squared minus 1.
01:36
That's going to be minus one, zero, one, right? and then the third column vector that we'll need in order to get a 2x minus one, that's going to be equal to 0 to minus one, oh sorry, typo.
01:56
So the top one is going to be minus one, and then two, and then zero...