Let $E=\{x \in \mathbb{R}: 0 \leq x \leq 1\}$ and let $f(x)=\left(1+x^2\right) / 2$. Show that:
(a) $f$ maps $E$ into $E$.
(b) There does not exist a positive constant $\gamma<1$ such that $|f(b)-f(a)| \leq \gamma|b-a|$ for every choice of $a, b \in E$.
(c) $f$ has exactly one fixed point $x_* \in E$.