Let $f : A \rightarrow B, g : B \rightarrow C,$ and $h : C \rightarrow D .$ Prove that $h \circ(g \circ f)=$ $(h \circ g) \circ f(\text { associative property })$ [Hint: Verify that $(h \circ(g \circ f))(x)=((h \circ g) \circ f)(x)$ for every $x$ in $A . ]$