Question
Let $F$ and $V$ denote the focus and the vertex, respectively, of the parabola $x^{2}=4 p y .$ If $\overline{P Q}$ is a focal chord of the parabola, show that$$P F \cdot F Q=V F \cdot P Q$$
Step 1
The given equation of the parabola is \( x^2 = 4py \). The vertex \( V \) of the parabola is at the origin \( (0, 0) \), and the focus \( F \) is at the point \( (0, p) \). Show more…
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Let $F$ be the focus of the parabola $x^{2}=8 y,$ and let $P$ denote the point on the parabola with coordinates $(8,8) .$ Let $\overline{P Q}$ be a focal chord. If $V$ denotes the vertex of the parabola, verify that $$ P F \cdot F Q=V F \cdot P Q $$
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Let $F$ be the focus of the parabola $x^{2}=8 y,$ and let $P$ denote the point on the parabola with coordinates $(8,8) .$ Let $overline{P Q}$ be a focal chord. If $V$ denotes the vertex of the parabola, verify that $$P F cdot F Q=V F cdot P Q$$
If $\overline{P Q}$ is a focal chord of the parabola $y^{2}=4 p x$ and the coordinates of $P$ are $\left(x_{0}, y_{0}\right),$ show that the coordinates of $Q$ are $$ \left(\frac{p^{2}}{x_{0}}, \frac{-4 p^{2}}{y_{0}}\right) $$.
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