00:01
For this problem, we are first asked to determine whether or not the given vector field is conservative.
00:06
I'll label our different components as m, n, and p.
00:09
We'll start by taking the partial derivative of m with respect to y, which would give us 2x, and with respect to z, which would give us 2z.
00:22
Then of n with respect to x, which gives us 2x, and n with respect to z, which gives us 0, p with respect to x, which gives us 2z, and p with respect to y, which gives us 0.
00:42
Now, this will be conservative if, first, we have my equals nx, which is true.
00:49
Then if mz equals px, which we can see is true.
00:56
And if nz equals py, which we can see is true...