Question
Let $F$ be a finite field of order $q$ and let $a$ be a nonzero element in $F$. If $n$ divides $q-1$, prove that the equation $x^{n}=a$ has either no solutions in $F$ or $n$ distinct solutions in $F$.
Step 1
Let \( g \) be a generator of this group. Then every nonzero element \( a \in F \) can be expressed as \( a = g^k \) for some integer \( k \) where \( 0 \leq k < q-1 \). Show more…
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