Question
Let $f$ denote the density function and $h$ the hazard function of a nonnegative random variable. Show that$$f(t)=h(t) e^{-\int_{0}^{t} h(s) d s}$$that is, that the hazard function uniquely determines the density.
Step 1
The hazard function $h(t)$ is defined as the ratio of the density function $f(t)$ to the survival function $1-F(t)$, where $F(t)$ is the cumulative distribution function. So, we have: $$ h(t) = \frac{f(t)}{1-F(t)} $$ Show more…
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Summary
Let $X$ have the density function $f,$ and let $Y=X$ with probability $\frac{1}{2}$ and $Y=-X$ with probability $\frac{1}{2} .$ Show that the density of $Y$ is symmetric about zero - that is, $f_{Y}(y)=f_{Y}(-y)$
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