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Let $f, g$ be two isometries. Show that the composition $f \circ g$ is again an isometry. (This says the set of isometries is closed under composition.)

   Let $f, g$ be two isometries. Show that the composition $f \circ g$ is again an isometry. (This says the set of isometries is closed under composition.)
Exploring Geometry
Exploring Geometry
Michael Hvidsten 2nd Edition
Chapter 5, Problem 4 ↓

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An isometry is a function that preserves distances between points. Mathematically, if $f$ is an isometry, then for any points $x$ and $y$ in the domain of $f$, we have $d(f(x), f(y)) = d(x, y)$, where $d$ denotes the distance function.  Show more…

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Let $f, g$ be two isometries. Show that the composition $f \circ g$ is again an isometry. (This says the set of isometries is closed under composition.)
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Key Concepts

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Distance Preservation Under Composition
When composing two isometries, the distance preservation property is maintained. Since each isometry individually preserves distances, applying one after the other results in a transformation that still keeps all distances unchanged. This closure under composition is an important property in the study of symmetry and group theory in metric spaces.
Isometry
An isometry is a function between metric spaces that preserves distances; that is, for any two points, the distance between their images under the function is equal to the distance between the points themselves. This fundamental property makes isometries important in geometry and analysis, as they maintain the structure of the space.
Composition of Functions
The composition of functions is an operation where one function is applied after another. If we have functions f and g, their composition f ? g is defined by applying g first and then f. Understanding function composition is key in many areas of mathematics because it allows the building of complex transformations from simpler ones.

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a). Show that every isometry is a one-to-one function. (In other words, show that if f is an isometry and P and Q are points with P ≠ Q then f(P) ≠ f(Q)). b) Assume that f is an isometry and that it has an inverse function f⁻¹. Show that f⁻¹ also is an isometry. (Exercise 1.10.2 shows that every isometry does, in fact, have an inverse).

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