00:01
In this problem, we have been given a statement.
00:02
We need to prove it by mathematical induction.
00:05
And here, fn represents the nth fibonacci number.
00:09
So let's consider the given statement to be tn.
00:13
So the statement is that f0 plus f1 and so on up to fn.
00:19
This is equal to fn plus 2 minus 1.
00:22
So first of all, let's consider the base case.
00:26
So we're going to show that t0 holds.
00:29
So on the left hand side we're just going to have f 0 because n is 0 so we just have f 0 and f 0 is given to be 0 and if we consider the right hand side so that's f n plus 2 minus 1 so f 0 plus 2 minus 1 so that's f 2 minus 1 so what what is f2? well, f2 is going to be f0 plus f1.
00:57
And f0 is equal to 0.
01:00
F1 is equal to 1.
01:02
So we end up with 1 minus 1, which is 0.
01:05
So we can see that the left -hand side is equal to the right -hand side...