00:01
Okay, good day, ladies and gentlemen.
00:05
Today we're going to look at a problem that is a proof, basically, which can ask us to prove.
00:13
You know, we're assuming that is positive, continuous and decreasing, and that we have this property here, this property here.
00:25
And we know that this converges to us, that we want to show that our end.
00:33
Here is less than i guess this is this integral here.
00:39
Okay, so first point i want to make here is that since the series converges we know from one of our, from one of the earlier results that this integral actually exists.
00:57
And this is this is pretty important to do anything really you need to know that the integral itself exist, which of course means then that this integral also exists.
01:14
So we can talk about this guy unambiguously and everything we do.
01:21
So that's pretty important.
01:23
That's pretty important in the whole thing.
01:26
So next, i want to point out something that i've talked about earlier and i'll just point it out again.
01:37
Now, what we're doing here is really what we've called before lower remand sums.
01:47
So this is lower remand sums, okay? and i think by now you should have done these for other cases.
02:02
The idea is that if you have an integral, you can approximate it from both above and below.
02:15
So if you know the integral exists, you can approximate it from above and below by what we call remand.
02:22
Sums and the basic idea is you start with now lower remon sums basically we set out some points in this case i have n minus one and and plus one and plus two and you draw these rectangles here now the difference here or the the length here is is what we sometimes refer to as delta act in this case, it's equal to one.
02:56
And the height here is, of course, equal to f of n.
03:03
The lower remand sums mean we use this point here, this endpoint...