Let $f:(a, b) \rightarrow \mathbb{R}$ and $c \in(a, b) .$ Show that the following are equivalent:
(i) $f$ is differentiable at $c$.
(ii) There exist $\alpha \in \mathbb{R}, \delta>0$ and a function $\epsilon_{1}:(-\delta, \delta) \rightarrow \mathbb{R}$ such that
$f(c+h)=f(c)+\alpha h+h \epsilon_{1}(h)$ for all $h \in(-\delta, \delta)$ and $\lim _{h \rightarrow 0} \epsilon_{1}(h)=0$
(iii) There exists $\alpha \in \mathbb{R}$ such that
$$
\lim _{h \rightarrow 0} \frac{|f(c+h)-f(c)-\alpha h|}{|h|}=0
$$
If the above conditions hold, then show that $f^{\prime}(c)=\alpha$.