00:01
All right, so the first step here, since f is going to be remand integral by the archimedes remand theorem, we have that the phenum p .u of f .p is equal to the supremum pl of f .p, which is equal to the integral from a to b of f of fx d .s.
00:29
And this means that upper sums can be made arbitrarily close above the integral, and lower sums can be made arbitrarily close below the integral.
00:41
And then because of the infirmum and the supremum, there's going to exist a partition p1 such that u of f, b1, is going to be less than the integral from a to b of fx, x, x, x, plus epsilon over 2, and there's going to exist a partition p2, such that l of f, p2, is going to be greater than the integral from a to b of f of x, x, x minus epsilon over 2.
01:20
Then we can take a common refinement.
01:22
We let p be equal to the union of p1 and p2...