Question
Let $f(t)=\frac{9}{5} t+32$. This function converts temperature from ${ }^{\circ} \mathrm{C}$ to ${ }^{\circ} \mathrm{F}$. Evaluate $f(0), f(100)$ and $f(24)$.
Step 1
First, let's evaluate $f(0)$: $f(0) = \frac{9}{5}(0) + 32 = 0 + 32 = 32$ So, $0^{\circ}\mathrm{C}$ is equal to $32^{\circ}\mathrm{F}$. Show more…
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