Let $f(x)$ belong to $F[x]$, where $F$ is a field. Let $a$ be a zero of $f(x)$ of multiplicity $n$, and write $f(x)=(x-a)^{n} q(x)$. If $b \neq a$ is a zero of $q(x)$, show that $b$ has the same multiplicity as a zero of $q(x)$ as it does for $f(x)$. (This exercise is referred to in this chapter.)