Question
Let $f(x)=$ minimum $\left\{e^{x}, 3 / 2,1+e^{-x}\right\}, 0 \leq x \leq 1$. Find the area bounded by $y=f(x), X$ -axis, $Y$ -axis and the line $x=1$
Step 1
We find that $e^{x}$ is the minimum for $0 \leq x \leq \log(3/2)$, $3/2$ is the minimum for $\log(3/2) \leq x \leq \log 2$, and $1+e^{-x}$ is the minimum for $\log 2 \leq x \leq 1$. Show more…
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