Step 2:
For part (a), we need to evaluate $f(1,1,1)$. Let's substitute $x=1$, $y=1$, and $z=1$ into the function.
$f(1,1,1) = \sqrt{1} + \sqrt{1} + \sqrt{1} + \ln(4-1^2-1^2-1^2)$
$f(1,1,1) = 1 + 1 + 1 + \ln(4-3)$
$f(1,1,1) = 3 + \ln(1)$
$f(1,1,1) = 3 + 0 =
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