00:01
So here we have a function, we're defining as f x of y, and it is equal to 1 plus the square root of 4 minus y squared.
00:22
All right, so the first thing we can do is evaluate it at the point 3 .1.
00:28
So one thing to note here is that there is an x in the sense that it is in two dimensions.
00:37
However, there's no x in the actual domain.
00:40
So when we're doing the fx of y, we don't really need to worry about that.
00:45
So it would be just 4 minus 1 because that's 1 squared.
00:50
And so when we simplify this, we get 1 plus the square root of 3 just to leave everything exact.
00:57
So the next thing we can do is find the domain of this.
01:00
So when we're finding the domain, we know that the x, or for x, the domain, is all of x, because there is no x that's serving as any sort of limiting factor for the function.
01:16
And then in y, the domain for y is only defined from the points negative two to two...