00:02
For the function f of x equals 1 over x, we're looking for the interval 1 to b.
00:09
We want to find out what is that b such that the average rate of change equals negative 1 fifth.
00:15
So the average rate of change is equal to the slope of the line connecting those two points, 1 comma f of 1 and b comma f of b.
00:27
So we want f of b minus f of 1.
00:34
That's the rise over the run, which is b minus 1.
00:41
And that equals, well, f of b is 1 over b minus f of 1 is 1 over 1, and all of that's still over b minus 1.
00:53
So that's our average rate of change in terms of b, and we want that to equal negative 1 over 5.
01:03
So there are a couple of ways we can approach this.
01:08
Probably the easiest is to, let's clean it up just a little tiny bit and call it 1 over b minus 1 over b minus 1 equals negative 1 fifth.
01:21
And from there, we can cross multiply.
01:26
We'll multiply both sides by 5 and we'll also multiply both sides by b minus 1.
01:31
So we're going to end up with 5 times 1 over b minus 1 equals negative 1 times b minus 1...