00:01
Hello, so first we take our given function and compute its derivative, and we find that f prime of x is going to be equal to while we get two.
00:12
So our function is two, e to the x minus six prime.
00:16
So that's going to be two times e to the x and then minus six.
00:22
Okay, so there is our derivative f prime.
00:25
And we take our derivative, we set it equal to zero.
00:28
So we add six to both sides, and we have two.
00:31
Times e to the x is equal to 6, dividing 3 by 2 gives us that e to the x is equal to 3.
00:38
Okay, so if e to the x is equal to 3, that x is then going to be equal to the natural log of 3.
00:48
So we then substitute in the natural log of 3 for x in our function, and we have f of the natural log of 3 is going to be equal to 2 times 3.
01:01
Minus six times the natural log of 3.
01:03
So that's equal to 6 minus 6 times the natural log of 3.
01:09
So therefore, the point at which the tangent line is horizontal is going to be at the point natural log of 3, comma, and then the other is the first, there's the x coordinate, and the y coordinate is going to be 6 minus 6 times the natural log of 3.
01:29
There's a point.
01:30
Ln of 3, comma 6 minus 6 times the network of 3.
01:35
Okay, then for part b, we want to set our function, or set our derivative equal to 12.
01:43
So we have f prime equal to 12.
01:45
So we have 2 times e to the x minus 6 equal to 12...