Question
Let $f(x)=2 \tan ^{-1}\left(\frac{1+x}{1-x}\right)+\sin ^{-1}\left(\frac{1-x^{2}}{1+x^{2}}\right)$for $0 \leq x<1$. Then find the value of $f\left(\frac{1}{2}\right)$
Step 1
Step 1: We are given the function $f(x)=2 \tan ^{-1}\left(\frac{1+x}{1-x}\right)+\sin ^{-1}\left(\frac{1-x^{2}}{1+x^{2}}\right)$. Show more…
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