Question

Let $f(x)=|6-3 x|-2$. Determine $f(1.3)$.

Name: Problem 116, Chapter 6: Intermediate Algebra for College Students
Uploaded: 2020-06-08T05:19:10-08:00
Duration: 26 s
Channel: Amy Jiang
Description: Let f(x)=|6-3 x|-2. Determine f(1.3).

   Let $f(x)=|6-3 x|-2$. Determine $f(1.3)$.

Intermediate Algebra for College Students

Allen R. Angel;… 10th Edition

Chapter 6, Problem 116

Instant Answer

Solved by Expert Amy Jiang

06/08/2020

Step 1

So, we have: $f(1.3) = |6 - 3(1.3)| - 2$ Now, we need to calculate the value inside the absolute value: $6 - 3(1.3) = 6 - 3.9 = 2.1$ Now, we have: $f(1.3) = |2.1| - 2$ Since the absolute value of 2.1 is just 2.1, we can continue: $f(1.3) = 2.1 - 2$ Show more…

Show all steps

Thanks for your feedback!

Let $f(x)=|6-3 x|-2$. Determine $f(1.3)$.

Play audio

Feedback

Amy Jiang and 93 other educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Algebraic Manipulation

Algebraic manipulation encompasses the techniques used to simplify and solve expressions and equations. This includes operations such as substitution, distribution, and handling of absolute values, which are necessary skills for evaluating functions accurately.

Function Evaluation

Function evaluation is the process of substituting a specific input value into a function’s expression to compute the corresponding output. This is a core concept in mathematics that involves replacing the variable in a function with a given number and simplifying the resulting expression.

Absolute Value Function

The absolute value function transforms any real number into its non-negative counterpart, which is essential when determining outcomes that must be non-negative regardless of the sign of the input. It is often defined piecewise to handle both negative and non-negative inputs.

Please give Ace some feedback