00:01
Let us consider the f of x a x square plus b x plus c is an integer whenever x is an integer.
00:16
First let us assume like that.
00:19
Then f of 0, f of 1, f of minus 1, all are integer since instead of x we took 0, 1, 1, 1, 1 1 1 1, minus 1 which are integers therefore the function value is also integer what is f of 0 that is c what is f of 1 that is a plus b plus c and f of minus 1 is a minus b plus c these all are integers c is already an integer a plus b plus c is an integer.
01:00
This is an integer.
01:01
Therefore, a plus b should be an integer.
01:04
Similarly, a minus b should be an integer.
01:06
So, c, a plus b, a minus b are inditures.
01:13
The sum of two integers is again an integer.
01:17
So, sum of these two, a plus b plus a minus b, is again an integer...