Let $f(x)=e^{v+1 / n}-e^{x}$ for real number $p>0$.
Let $g(t)=\int_{1}^{1+1} f(x) e^{1-x} d x .$ The value of $t=t_{p}$, for which $\mathrm{g}(\mathrm{t})$ is minimum is
(A) $-\ln \left(\frac{\mathrm{e}^{p}-1}{\mathrm{p}}\right)$
(B) $-\frac{1}{p} \ln \left(\frac{e^{p}-1}{p}\right)$
$(C)-\frac{1}{p} \ln \left(\frac{(p+1)\left(e^{p}-1\right)}{p}\right)$
(D) $-\ln \left((p+1)\left(\mathrm{e}^{p}-1\right)\right)$