According to the definition of function composition, we have $(f \circ g)(x) = f(g(x))$. Substituting $g(x) = \frac{3}{x-1}$ into $f(x)$, we get
\[(f \circ g)(x) = f\left(\frac{3}{x-1}\right) = \frac{2}{\frac{3}{x-1}} = \frac{2(x-1)}{3}.\]
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